下载 12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26

请下载并共享12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26，它是类别桌面和棋类中的特色游戏之一。
另外，还有一些其他游戏可以作为Rolling Sky + MOD (Balls/Shield/Key) v8.6.4 MOD APK, Chess · Play & Learn + Mod (保费) v4.1.8 MOD APK, Stockfish Chess Engine (OEX), Ubongo Puzzle Challenge Mod Full v1.4.0 MOD APK, Chess Coach Pro Mod (Professional version) MOD APK, Ludo Club - Fun Dice Game下载。如果您对12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26感到满意。

12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26发布，12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26是当今最好的免费和最佳手机应用程序之一。位于应用商店的桌面和棋类类别中。

12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26的最低操作系统为Android 4.2+及更高版本。因此，如果尚未升级手机，则必须更新。

在APKDroid上，您将免费下载12 Beads (12 Tini/Sholo Guti/12 Daane) - v1.0.26 APK，最新版本为1.0.26，发布日期为2020-06-28，文件大小为5.6 MB。根据Google Play商店的统计数据，大约有1000次下载。您可以根据需要更新在Android上单独下载或安装的应用。还可以更新您的应用。您可以使用最新功能并提高安全性和应用程序的稳定性。现在就享受它

12 Beads (12 Tini/Sholo Guti/12 Daane) Game

In this game two player can participate. Both players will have 12 beads, which they have to save from opposite player. One player turn first and second player needs to wait till his/her turn. When both player register, game starts automatically. After that the first player must move his/her bead to nearest destination but, initially player need to choose his/her bead.

Players can move their bead in two ways, which are following.
1. By moving nearest bead.
2. By crossing another player's bead.

In first way players can save their bead from another player.

Note: Players can move bead to nearest place only once in their single turn.

In Second way players can cross another's player bead if nearest bead is opponent's bead and crossed location is empty, in other words there is no any bead in crossed point. After crossing bead, player need to pass turn by clicking on PASS button or by clicking on a bead which he/she moved after crossed

Note: Players can crossed more than one bead in their single turn.

Result will depend on which player will lose first his/her all 12 beads. For Instance: if player first will lose his/her bead than winner is player second."

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